Total 6 dices are given {I,II,III,IV,V,VI}
A dice has {1,2,3,4,5,6} on their 6 distinct faces .
Condition I :Given that sum of opposite faces of dice is 7 .
Condition II :Odd numbered dices have even number on their top face.
lets use the logic of condition I and condition II :
I Dice : (3,4) (6,1) are given , so the other pair has to be (2,5), And using condition II, now we can say Top face is 2.
II Dice : (5,2) (4,3) are given, so the other pair has to be (1,6) .
III Dice : (6,1) (4,3) are given, so the other pair has to be (2,5),And using condition II, we can say Top face is 2.
IV Dice : (2,5) (4,3) are given, so the other pair has to be (1,6).
V Dice : (1,6) (2,5) are given, so the other pair has to be (4,3),And using condition II, we can say Top face is 4.
VI Dice : (4,3) (5,2) are given, so the other pair has to be (1,6).
Therefore, the sum of dots on odd numbered dices = 2+2+4 = 8.
