Question 7.ShareReportIf 1212x×424x+12×52y=84z×2012x×2433x−612^{12x}\times4^{24x+12}\times5^{2y}=8^{4z}\times20^{12x}\times243^{3x-6}1212x×424x+12×52y=84z×2012x×2433x−6 where x, y and z are natural numbers, then x+y+zx+y+zx+y+z equalsABCDBackspace7894561230.-Clear AllSubmit Previous QuestionRate this SolutionNext Question Question ExplanationVideo ExplanationNo video explanation yet — we're on it and uploading soon!