Question 6.

For real values of x, the range of the function

f(x)=\frac{2x-3}{2x^{2}+4x-6}

(-\infty,\frac{1}{8}]\cup[1,\infty)

(-\infty,\frac{1}{8}]\cup[\frac{1}{2},\infty)

(-\infty,\frac{1}{4}]\cup[\frac{1}{2},\infty)

(-\infty,\frac{1}{4}]\cup[1,\infty)

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