Question 15.

Two places A and B are 45 kms apart and connected by a straight road. Anil goes from A to B while Sunil goes from B to A. Starting at the same time, they cross each other in exactly 1 hour 30 minutes. If Anil reaches B exactly 1 hour 15 minutes after Sunil reaches A, the speed of Anil, in km per hour, is

A
18
B
16
C
14
D
12

Question Explanation

Text Explanation

We can use the formula for when two people moving towards each other and meeting in a straight line. t2=t1× t2t^2=t_1\times\ t_2

Where tt is time taken for them to meet each other. t1t_1 is the time taken by person 1 to reach the destination after meeting and 

t2t_2 is the time taken by person 2 to reach the destination after meeting

We are told they meet each other in 1 and a half hours, that is 90 minutes. 

And if Sunil takes X minutes to reach A, Anil will take X+75 minutes

Since it is given that, Anil reaches B exactly 1 hour 15 minutes after Sunil reaches A

902=x(x+75)90^2=x\left(x+75\right)

8100=x2+75x8100=x^2+75x

x2+75x8100=0x^2+75x-8100=0

(75±5625+32400)2\dfrac{\left(-75\pm\sqrt{5625+32400}\right)}{2}

(75+195)2\dfrac{\left(-75+195\right)}{2}

x=60x=60

Total time of travel of Anil is, 90 min +60 min +75 min90\ \min\ +60\ \min\ +75\ \min

Total of 225 minutes. 

Time in hours will be 3.75 hours. 

Speed is 453.75=12 kmhr\dfrac{45}{3.75}=12\ \dfrac{km}{hr}

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