Question 11.

A trapezium ABCD has side AD parallel to BC,BAD=90,BC=3 cm\text{BC}, \angle \text{BAD}=90^{\circ}, \text{BC}=3 \text{~cm} and AD=8~cm . If the perimeter of this trapezium is 36~cm, then its area, in sq.cm, is

A
B
C
D

Question Explanation

Text Explanation

CD = y2+25\sqrt{y^2 + 25}

11+y+y2+25=3611 + y + \sqrt{y^2 + 25} = 36

y2+25=25y\sqrt{y^2 + 25} = 25 - y

y2+25=252+y250yy^2 + 25 = 25^2 + y^2 - 50y

2y=242y = 24

y = 12

Video Explanation
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