Question 9.ShareReportIf log64x2+log8y+3log512(yz)=4\log_{64}x^{2}+\log_{8}\sqrt{y}+3\log_{512}(\sqrt{y}z)=4log64x2+log8y+3log512(yz)=4 where x, y and z are positive real numbers, then the minimum possible value of (x+y+z)(x+y+z)(x+y+z) isA36B24C48D96Backspace7894561230.-Clear AllSubmit Previous QuestionRate this SolutionNext Question Question ExplanationVideo ExplanationNo video explanation yet — we're on it and uploading soon!