Question 4.

In a circle with centre CC and radius 626\sqrt{2} cm, PQPQ and SRSR are two parallel chords perpendicular to one of the diameters. PQC=45\angle PQC = 45^{\circ}, and the ratio of the perpendicular distances of PQPQ and SRSR from CC is 3:23:2. Then, the area, in sq. cm, of the quadrilateral PQRSPQRS is:

A
20(32+7)20(3\sqrt{2} + \sqrt{7})
B
4(32+7)4(3\sqrt{2} + \sqrt{7})
C
4(3+14)4(3 + \sqrt{14})
D
20(3+14)20(3+\sqrt{14})

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