Question 24.

In a trepezium ABCD, AB is parallel to DC, BC is perpendicular to DC and ∠BAD = 45°. If DC = 5 cm, BC = 4 cm, the area of the trepezium in sq. cm is

A
B
C
D

Question Explanation

Text Explanation


Given, BC = DE = 4

CD = BE = 5

In triangle ADE, EAD=45045^{0}

tan⁡ 45 = DEAE\frac{DE}{AE} => AE = 4

Area of trapezium = Area of rectangle BCDE + Area of triangle AED

= 20 + 8 = 28

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