Question 20.ShareReportA value of ccc for which the minimum value of f(x)=x2−4cx+8cf(x) = x^2 - 4cx + 8cf(x)=x2−4cx+8c is greater than the maximum value of g(x)=−x2+3cx−2cg(x) = -x^2 + 3cx - 2cg(x)=−x2+3cx−2c, is .A-2B-12\frac{1}{2}21C2D12\frac{1}{2}21Backspace7894561230.-Clear AllSubmit Previous QuestionRate this SolutionNext Question Question ExplanationVideo ExplanationNo video explanation yet — we're on it and uploading soon!