Question 11.

In an election, there were four candidates and 80% of the registered voters casted their votes. One of the candidates received 30% of the casted votes while the other three candidates received the remaining casted votes in the proportion 1 : 2 : 3. If the winner of the election received 2512 votes more than the candidate with the second highest votes, then the number of registered voters was

A
40192
B
60288
C
50240
D
62800

Question Explanation

Text Explanation

Let the number of registered votes be 100x

The number of votes casted = 80x

Votes received by one of the candidates = 30100×80x=24x\frac{30}{100} \times 80x = 24x

Remaining votes = 80x24x=56x80x - 24x = 56x

Votes received by other three candidates is 56x6,2×56x6,3×56x6\frac{56x}{6}, \frac{2 \times 56x}{6}, \frac{3 \times 56x}{6}

It is given,

28x24x=251228x - 24x = 2512

4x=25124x = 2512

x = 628

The number of registered votes = 100x=62800100x = 62800

Video Explanation
XAT 2026 Full Course - Enroll Now for Best XAT Preparation
CAT LRDI 100 Recorded Course - Master Logical Reasoning and Data Interpretation
HOME
XAT Sankalp Sale
Quant Revision Book
More
YoutubeWhatsapp