Question 8.

For the same principal amount, the compound interest for two years at 5% per annum exceeds the simple interest for three years at 3% per annum by Rs 1125. Then the principal amount in rupees is

A
B
C
D

Question Explanation

Text Explanation

For two years the compound interest is 

PR(1)100+PR(1)100(1+PR(1)100)\frac{PR(1)}{100} + \frac{PR(1)}{100}\left(1 + \frac{PR(1)}{100}\right)

For three years the simple interest is 

9PR100\frac{9PR}{100}

Now R(1)= 5% and R = 3%

Hence 

5P100+5P100(1.05)9P100=1125\frac{5P}{100} + \frac{5P}{100}(1.05) - \frac{9P}{100} = 1125

4P100+5.25P100=1125-\frac{4P}{100} + \frac{5.25P}{100} = 1125

1.25P100=1125\frac{1.25P}{100} = 1125

Solving we get P = 90000

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