Question 28.
Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is
A
2 : 3
B
4 : 5
C
5 : 6
D
3 : 4
Question Explanation
Text ExplanationVideo Explanation
The given figure can be divided into 9 regions or equilateral triangles of equal areas as shown below,
Now the hexagon consists of 6 regions and the triangle consists of 9 regions.
Hence the ratio of areas = 6/9 =2:3
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