Question 2.

The number of ways of distributing 20 identical balloons among 4 children such that each child gets some balloons but no child gets an odd number of balloons, is

A
B
C
D

Question Explanation

Text Explanation

Let the number of balloons each child received be 2a, 2b, 2c and 2d

2a + 2b + 2c + 2d = 20

a + b + c + d = 10

Each of them should get more than zero balloons.

Therefore, total number of ways = (n1)Cr1=(101)C41=9C3=84 (n-1)C_{r-1} = (10-1)C_{4-1} = 9C_3 = 84

Video Explanation
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