Question 1.
Let ABCD be a parallelogram such that the coordinates of its three vertices A, B, C are (1, 1), (3, 4) and (−2, 8), respectively. Then, the coordinates of the vertex D are
A
(−4, 5)
B
(4, 5)
C
(−3, 4)
D
(0, 11)
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In a parallelogram, two diagonals of parallelogram bisects each other, which concludes that mid-point of both diagonals are the same.
Midpoint of AC = ()
Let the coordinates of vertex D be (x, y)
() = ()
x = -4 and y = 5
The answer is option D.



