Question 12.

Assuming m is even, then 8f(m+1)-f(m)=2

m+1 will be odd

So, 8(m+1+3)-m(m+1)=2

=> 8m+32-$m^2$−m=2

=> $m^2−7m−30=0$

=> m=10,-3 

Rejecting the negative value, we get m=10

Assuming m is odd, m+1 will be even.

then, 8(m+1)(m+2)-m-3=2

=> 8($m^2$+3m+2)-m-3=2

=> $8m^2+23m+11=0$

Solving this, m = -2.26 and -0.60

Hence, the value of m is not integral. Hence this case will be rejected.