Statement I: Bank A:&nbsp;r = 6.2% and compounded anually Compound interest at the end of an year =&nbsp;$P\left(1+\frac{6.2}{100}\right)-P=\frac{6.2P}{100}$ Bank B:&nbsp;r = 6% and compounded semi-anually C.I =&nbsp;$P\left(1+\frac{3}{100}\right)^2-P=\frac{P\left(6.09\right)}{100}$ Interest is less in bank B. Therefore, statement I is correct. Statement II: Let the sum of money be 'S' It is given, $S\left(1+\frac{r}{100}\right)^3=2S$ $\left(1+\frac{r}{100}\right)^3=2$ $\left(1+\frac{r}{100}\right)^9=8$ $S\left(1+\frac{r}{100}\right)^9=8S$ Therefore, P = 8 Statement II is incorrect. The answer is option C.

F(x) = |2x| + 4Option A: G(x) = x + 3If x &gt; 0 or x = 02x + 4 = x + 3x = -1 &lt; 0Therefore, this case is not possible.If x &lt; 0-2x + 4 = x + 33x = 1x = 1/3 &gt; 0Therefore, this case is not possible.Option B: G(x) = 2x - 2If x &gt; 0 or x = 02x + 4 = 2x - 2This case is not possible.If x &lt; 0-2x + 4 = 2x - 2x = 1.5 &gt; 0This case is not possible.Option C: G(x) = 2x + 3If x &gt; 0 or x = 02x + 4 = 2x + 3This case is not possible.If x &lt; 0-2x + 4 = 2x + 3x = 0.25 &gt; 0This case is not possible.Option D: G(x) = 3x - 2If x &gt; 0 or x = 02x + 4 = 3x - 2x = 6This case is possible.Therefore, the answer is option D.

It is given, 320SP = 400CP 4SP = 5CP Profit percentage =&nbsp;$\ \frac{\ SP-CP}{CP}\times100=\ \frac{\ \frac{5CP}{4}-CP}{CP}\times100=25\%$ The answer is option D.

In 2020:Cost of component A =&nbsp;$\frac{90}{360}\times12000=3000$Cost of component B =&nbsp;$\frac{120}{360}\times12000=4000$Cost of component C =&nbsp;$\frac{150}{360}\times12000=5000$In 2021:Cost of component A = 1.1*3000 = Rs&nbsp;3300Cost of component B = 1.2*4000 = Rs 4800Cost of component C = 1.1*5000 = Rs 5500The answer is option B.

A - 2 terms B - 4 terms C - 6 terms .. 2 + 4 + 6 + ..... 2n terms&nbsp;=&gt; this sum should be greater than or equal to 95. $2\left(1+2+3+...+n\right)\ge\ 95$ $n\left(n+1\right)\ge\ 95$ If n = 9, we get only 90 terms. 95th term occurs when n = 10, i.e. J. The answer is option C.

Let the amount invested be 'P' and the rate of interest be 'r'.Simple interest =$\ \frac{\ P\times r\times2}{100}$, which is equal to 800=&gt; $\frac{\Pr}{100}=400$Compound interest =&nbsp;$P\left(1+\frac{r}{100}\right)^2-P$ = 900$P\left(\frac{r}{100}\right)^2+\frac{2\Pr}{100}=900$$P\left(\frac{r}{100}\right)^2=100$$400\left(\frac{r}{100}\right)=100$r = 25%P =&nbsp;$\frac{400\left(100\right)}{25}$ = Rs 1600The answer is option B.

It is given, x &gt; 03.6% of&nbsp;$\frac{5x}{12}$ =&nbsp;$\frac{3.6}{100}\times\frac{5x}{12}=\frac{36}{1000}\times\frac{5x}{12}=\frac{3x}{200}$A) 3 percent of 20x =&nbsp;$\frac{3\left(20x\right)}{100}=\frac{3x}{5}$ ≠ $\frac{3x}{200}$B) x percent of&nbsp;$\frac{3}{2}$ =&nbsp;$\frac{x}{100}\left(\frac{3}{2}\right)=\frac{3x}{200}$C) 3x percent of 0.2 =&nbsp;$\frac{3x}{100}\left(0.2\right)=\frac{6x}{1000}=\frac{3x}{500}$ ≠ $\frac{3x}{200}$D) 0.05 percent of 3x =&nbsp;$\frac{0.05}{100}\left(3x\right)=\frac{3x\left(5\right)}{10000}=\frac{3x}{2000}$ ≠ $\frac{3x}{200}$E)&nbsp;$\frac{3x}{200}$Only B and E are equal to the calculated value.Therefore, the answer is option D.

Statement I:Let the actual time taken by Ravi to reach the college be 't'.If Ravi travels at a speed of 5 km/hr, time taken is t +&nbsp;$\frac{10}{60}$If Ravi travels at a speed of 6 km/hr, time taken is t -&nbsp;$\frac{4}{60}$Distance = speed*time = P =&nbsp;$5\left(t+\frac{10}{60}\right)=6\left(t-\frac{4}{60}\right)$$5\left(t+\frac{10}{60}\right)=6\left(t-\frac{4}{60}\right)$$5t+\frac{50}{60}=6t-\frac{24}{60}$$t=\frac{74}{60}$Distance(P) =&nbsp;$5\left(\frac{74}{60}+\frac{10}{60}\right)=5\left(\frac{84}{60}\right)=7$ kmTherefore, statement I is incorrect.Statement II:Let the speed of Babita be 3x.The speed of Amit is 7x.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/12/image_L0iQh9n.png">B covers distance y.&nbsp;In the same time, A should cover 80+y.$\frac{y}{3x}=\ \frac{\ 80+y}{7x}$7y = 240 + 3y4y = 240y = 60Total distance = 80 + 60 = 140mTherefore, statement II is correct.The answer is option D.

It is given, a + b + c = 96 and&nbsp;$a\le\ b\le\ c$ It is also given that age of Q is 6 years more than the age of P, i.e. b = a + 6 Minimum value c can take is equal to b, i.e. a + 6 a + a + 6 + a + 6 = 96 3a = 84 a = 28 Minimum possible value of c = 28 + 6 = 34 years The answer is option A.

Total number of 8-letter words possible using letters S, Y, L, L, A, B, U, S is&nbsp;$\dfrac{8!}{2!2!}$ Statement I: We can find total number of 8-letter words by considering 2 S's as a single unit and arranging 7 units, i.e. (SS), Y, L, L, A, B, U Total number of ways =&nbsp;$\dfrac{7!}{2!}$ Required probability =&nbsp;$\ \dfrac{\ \dfrac{7!}{2!}}{\dfrac{8!}{2!2!}}=\dfrac{2}{8}=\dfrac{1}{4}$ Therefore, statement I is correct. Statement II: We can find total number of 8-letter words such that L's are at ends by arranging remaining 6 letters in the middle. Total number of ways =&nbsp;$\dfrac{6!}{2!}$ Required probability =&nbsp;$\ \dfrac{\ \dfrac{6!}{2!}}{\dfrac{8!}{2!2!}}=\dfrac{2}{56}=\dfrac{1}{28}$ Therefore, statement II is correct. The answer is option A.

cmat 2023 Complete Paper Solution | Slot 2

Instructions

Question 1.

Question 2.

Question 3.

Question 4.

Question 5.

Question 6.

Question 7.

Question 8.

Question 9.

Question 10.

cmat 2023 Complete Paper Solution | Slot 2

Instructions

<div>Instructions <br />For the following questions answer them individually</div>

Question 1.

Question 2.

Question 3.

<div>If the selling price of 320 Web Cameras is equal to the cost price of 400 Web Cameras, then the percentage profit is :</div>

Question 4.

Question 5.

<div>What is the 95th term of the following letter series? <br />A, A, B, B, B, B,C, C,C, C,C, C, D, D, D, D, D, D, D, D, E, ...</div>

Question 6.

<div><p>A certain sum of money earns a simple interest of ₹ 800 over 2-year period. The same sum of money invested at the same rate of interest and same period on a compound interest basis earns an interest of ₹ 900. What is the sum?</p></div>

Question 7.

<div><p>If x &gt; 0, then which of the following expressions are equal to 3.6% of $\frac{5x}{12}$?<br>A. 3 percent of 20x<br>B. x percent of $\frac{3}{2}$<br>C. 3x percent of 0.2<br>D. 0.05 percent of 3x<br>E. $\frac{3x}{200}$<br>Choose the correct answer from the options given below:</p></div>

Question 8.

Question 9.

<div>Let a, b and c be the ages of three persons P, Q and R respectively where a $\leq$ b $\leq$ c are natural numbers. If the average age of P, Q, R is 32 years and if the age of Q is exactly 6 years more than that of P, then what is the minimum possible value of c?</div>

Question 10.