Question 9.

Let r and c be real numbers. If r and −r are roots of 5x3+cx210x+9=05 x^3+c x^2-10 x+9=0, then c equals

A
92-\frac{9}{2}
B
92\frac{9}{2}
C
-4
D
4

Question Explanation

Text Explanation

Let the roots of the given equation 5x3+cx210x+9=05x^3 + cx^2 - 10x + 9 = 0 be r, −r and p

r − r + p = c5-\frac{c}{5}

p = c5-\frac{c}{5} …… (1)

r2pr+pr=2-r^2 - pr + pr = -2

r2=2r^2 = 2 …… (2)

r2p=95-r^2 p = -\frac{9}{5}

p=910p = \frac{9}{10} …… (3)

Substituting p in (1), we get

910=c5\frac{9}{10} = -\frac{c}{5}

92=c-\frac{9}{2} = c

Video Explanation
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