Question 9.ShareReportIf a−6b+6c=4a - 6b + 6c = 4a−6b+6c=4 and 6a+3b−3c=506a + 3b - 3c = 506a+3b−3c=50, where aaa, bbb and ccc are real numbers, the value of 2a+3b−3c2a + 3b - 3c2a+3b−3c is.A15B18C14D20Backspace7894561230.-Clear AllSubmit Previous QuestionRate this SolutionNext Question Question ExplanationVideo ExplanationNo video explanation yet — we're on it and uploading soon!