Question 3.

We are given that average of three distinct integers is 28, that means the sum of these three integers is 28x3=84

Let us write $x+y+z=84$

x, y, z being the three distinct integers in ascending order. 

If the smallest number is increased by 7 and the largest number is reduced by 10

$(x+7)+(y)+(z-10)=81$

New arithmetic mean will be $\frac{81}{3}=27$

And this is said to be 2 more than the middle number, meaning

$27-2=y=25$

$x+z=59$

We are given that difference between the largest and the smallest numbers becomes 64, 

$(z-10)-(x+7)=64$

$z-x=81$

Adding the two equations we get, $2z=140$

$z=70$