Question 3.

The average of three distinct real numbers is 28. If the smallest number is increased by 7 and the largest number is reduced by 10, the order of the numbers remains unchanged, and the new arithmetic mean becomes 2 more than the middle number, while the difference between the largest and the smallest numbers becomes 64.Then, the largest number in the original set of three numbers is

A
B
C
D

Question Explanation

Text Explanation

We are given that average of three distinct integers is 28, that means the sum of these three integers is 28x3=84

Let us write x+y+z=84x+y+z=84

x, y, z being the three distinct integers in ascending order. 

If the smallest number is increased by 7 and the largest number is reduced by 10

(x+7)+(y)+(z10)=81(x+7)+(y)+(z-10)=81

New arithmetic mean will be 813=27\frac{81}{3}=27

And this is said to be 2 more than the middle number, meaning

272=y=2527-2=y=25

x+z=59x+z=59

We are given that difference between the largest and the smallest numbers becomes 64, 

(z10)(x+7)=64(z-10)-(x+7)=64

zx=81z-x=81

Adding the two equations we get, 2z=1402z=140

z=70z=70

Video Explanation

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