Question 23.

If (2n+1)+(2n+3)+(2n+5)+...+(2n+47)=5280(2n + 1) + (2n + 3) + (2n + 5) + ... + (2n + 47) = 5280, then whatis the value of 1+2+3+..+n?1 + 2 + 3 + .. + n?

A
B
C
D

Question Explanation

Text Explanation

Let us first find the number of terms 

47=1+(n-1)2

n=24

24*2n+1+3+5+....47=5280

48n+576=5280

48n=4704

n=98

Sum of first 98 terms = 98*99/2

=4851

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