Question 20.

For a sequence of real numbers x1x_1, x2x_2, ..., xnx_n, if x1x_1 - x2x_2 + x3x_3 - ... + (1)n+1(-1)^n + 1xnx_n = n2n^2 + 2n for all natural numbers n, then the sum x49x_49 + x50x_50 equals

A
2
B
-2
C
200
D
-200

Question Explanation

Text Explanation

Now as per the given series:

we get x1=1+2=3x_1 = 1 + 2 = 3

Now x1x2=8x_1 - x_2 = 8

so x2=5x_2 = -5

Now x1x2+x3=15x_1 - x_2 + x_3 = 15

so x3=7x_3 = 7

so we get xn=(1)n+1(2n+1)x_n = (-1)^{n+1}(2n + 1)

so x49=99x_{49} = 99 and x50=101x_{50} = -101

Therefore, x49+x50=2x_{49} + x_{50} = -2

Video Explanation
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