Question 19.

All the vertices of a rectangle lie on a circle of radius R. If the perimeter of the rectangle is P, then the area of the rectangle is

A
P222PR\frac{P^2}{2}-2 P R
B
P282R2\frac{P^2}{8}-2 R^2
C
P216R2\frac{P^2}{16}-R^2
D
P28R22\frac{P^2}{8}-\frac{R^2}{2}

Question Explanation

Text Explanation

A=lbA = lb

l2+b2=4r2l^2 + b^2 = 4r^2

P=2(l+b)P = 2(l + b)

P2=l+b\frac{P}{2} = l + b

Squaring on both the sides, we get

P24=l2+b2+2lb\frac{P^2}{4} = l^2 + b^2 + 2lb

P24=4r2+2lb\frac{P^2}{4} = 4r^2 + 2lb

P282r2=lb\frac{P^2}{8} - 2r^2 = lb

Video Explanation
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