Question 18.

If (x+62)12(x62)12=22(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}, then x equals

A
B
C
D

Question Explanation

Text Explanation

Squaring on both sides, we get:

x+6 2+x6 22(x272)12=8x+6\sqrt{\ 2}+x-6\sqrt{\ 2}-2\left(x^2-72\right)^{\frac{1}{2}}=8

x(x272)12=4x-\left(x^2-72\right)^{\frac{1}{2}}=4


Bringing x to the other side, we get:

(x272)12=4x-\left(x^2-72\right)^{\frac{1}{2}}=4-x

Squaring on both sides again, we get:

x272=16+x28xx^2-72=16+x^2-8x

8x=888x=88

x=11x=11

Therefore, 11 is the correct answer. 

Video Explanation
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