Question 17.

The number of integer solutions of the equation (x210)(x23x10)=1\left(x^2-10\right)^{\left(x^2-3 x-10\right)}=1 is

A
B
C
D

Question Explanation

Text Explanation

Case 1: When x2x^2 − 3x − 10 = 0 and x2x^2 − 10 ≠ 0

x2x^2 − 3x − 10 = 0 or, (x−5) (x+2) = 0

or, x= 5 or -2

Case 2: x2x^2 − 10 = 1

x2x^2 − 11 = 0

No integer solutions

Case 3: x2x^2 − 10 = −1 and x2x^2 − 3x − 10 is even

x2x^2 − 9 = 0

or, (x+3)(x-3) = 0

or, x = -3 and 3

for x = -3 and +3x2x^2 − 3x − 10 is even

In total 4 values of x satisfy the equations

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