Question 14.

If (3+22)(3+2 \sqrt{2}) is a root of the equation ax2+bx+c=0a x^2+b x+c=0, and (4+23)(4+2 \sqrt{3}) is a root of the equation ay2+my+n=0a y^2+m y+n=0, where a, b, c, m and n are integers, then the value of (bm+c2bn)\left(\frac{b}{m}+\frac{c-2 b}{n}\right) is

A
3
B
1
C
4
D
0

Question Explanation

Text Explanation

a,b,c,ma, b, c, m and nn are integers so if one root is 3+223 + 2\sqrt{2} then the other root is 3223 - 2\sqrt{2}

Sum of roots =6=ba= 6 = -\dfrac{b}{a} or b=6ab = -6a

Product of roots =1=ca= 1 = \dfrac{c}{a} or c=ac = a

a,b,c,ma, b, c, m and nn are integers so if one root is 4+234 + 2\sqrt{3} then the other root is 4234 - 2\sqrt{3}

Sum of roots =8=ma= 8 = -\dfrac{m}{a} or m=8am = -8a

product of roots =4=na= 4 = \dfrac{n}{a} or n=4an = 4a

(bm+(c2b)n\frac{b}{m} + \frac{(c-2b)}{n})

= 6a8a+a+12a4a\frac{6a}{8a} + \frac{a+12a}{4a} = 34+134=164=4\frac34 + \frac{13}{4} = \frac{16}{4} = 4

Video Explanation
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