Question 14.

A man buys 35 kg of sugar and sets a marked price in order to make a 20% profit. He sells 5 kg at this price, and 15 kg at a 10% discount. Accidentally, 3 kg of sugar is wasted. He sells the remaining sugar by raising the marked price by p percent so as to make an overall profit of 15%. Then p is nearest to

A
35
B
31
C
22
D
25

Question Explanation

Text Explanation

Let the cost price of 1kg of sugar = Rs 100

The total cost price of 35 kg = Rs3500

Marked up price per kg = Rs 120

Given, the final profit is 15% => Final SP of 35 kg = 3500 *1.15 = Rs 4025

First 5 kg's are sold at 20% marked up price => SP1=5⋅100⋅1.2 = Rs 600

Next 15 kgs are sold after giving 10% discount => SP2=15⋅100⋅1.2⋅0.9 = 1620

3kgs of sugar got wasted

=> 23 kg of sugar was sold at Rs (600 +1620) = Rs 2220

Remaining 12kg should be sold at Rs 4025 - 2220 = Rs 1805

=> SP of 1kg = 1805/12 ≃ 150

Hence, the seller should further mark up by (150120)120\frac{(150−120)}{120}⋅100 = 25%

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