Question 11.

Ravi is driving at a speed of 40 km/h on a road. Vijay is 54 meters behind Ravi and driving in the same direction as Ravi. Ashok is driving along the same road from the opposite direction at a speed of 50 km/h and is 225 meters away from Ravi. The speed, in km/h, at which Vijay should drive so that all the three cross each other at the same time, is

A
58.8
B
64.4
C
67.2
D
61.6

Question Explanation

Text Explanation

It is given that the speed of Ravi is 40 kmph, which is equal to 1009 \frac{100}{9} m/s. It is also known that the speed of Ashok is 50 kmph, which is equal to 1259 \frac{125}{9} m/s.

It is known that the distance between Ravi and Ashok is 225 meters, and the relative speed of Ravi and Ashok is 1259+1009=25 \frac{125}{9} + \frac{100}{9} = 25 m/s

Hence, they will meet each other in 22525=9 \frac{225}{25} = 9 seconds. The distance traveled by Ravi in these 9 seconds is 1009×9=100 \frac{100}{9} \times 9 = 100 meters.

Since Vijay was already 54 meters behind Ravi when they were starting, Vijay must travel (100+54) = 154 meters in these 9 seconds.

Hence, the speed of Vijay is 1549 \frac{154}{9} m/s, which is equal to 1549×185=3085=61.6 \frac{154}{9} \times \frac{18}{5} = \frac{308}{5} = 61.6 kmph.

The correct option is D

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