Question 11.

If (75)3xy=8752401\left(\sqrt{\frac{7}{5}}\right)^{3 x-y}=\frac{875}{2401} and (4ab)6xy=(2ab)y6x\left(\frac{4 a}{b}\right)^{6 x-y}=\left(\frac{2 a}{b}\right)^{y-6 x}, for all non-zero real values of a and b, then the value of x + y is

A
B
C
D

Question Explanation

Text Explanation

(75)3xy=8752401\left(\sqrt{\frac{7}{5}}\right)^{3x - y} = \frac{875}{2401}

(75)3xy2=125343\left(\frac{7}{5}\right)^{\frac{3x - y}{2}} = \frac{125}{343}

(75)3xy2=(75)3\left(\frac{7}{5}\right)^{\frac{3x - y}{2}} = \left(\frac{7}{5}\right)^{-3}

3x − y = −6

(4ab)6xy=(2ab)y6x\left(\frac{4a}{b}\right)^{6x - y} = \left(\frac{2a}{b}\right)^{y - 6x}

Therefore, y = 6x as the bases are different so the power should be zero for the results to be equal.

3x − y = −6

or, 3x − 6x = −6

or x = 2

y = 6x = 12

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