Question 6.

The number of real-valued solutions of the equation 2x2^x + 2x2^{-x} = 2 - (x2)2(x - 2)^2 is

A
infinite
B
0
C
1
D
2

Question Explanation

Text Explanation



The graphs of 2x+2x and 2(x2)22^x+2^{−x} \text{ and } 2−(x−2)^2

 never intersect. So, number of solutions=0.

Alternate method:

We notice that the minimum value of the term in the LHS will be greater than or equal to 2 {at x=0; LHS = 2}. However, the term in the RHS is less than or equal to 2 {at x=2; RHS = 2}. The values of x at which both the sides become 2 are distinct; hence, there are zero real-valued solutions to the above equation.

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