Question 18.

How many factors of 24×35×1042^4 \times 3^5 \times 10^4 are perfect squares which are greater than 1?

A
B
C
D

Question Explanation

Text Explanation

24×35×1042^4 \times 3^5 \times 10^4

=24×35×2454= 2^4 \times 3^5 \times 2^4 \ast 5^4

=28×35×54= 2^8 \times 3^5 \times 5^4

For the factor to be a perfect square, the factor should be an even power of the number.

In 282^8, the factors which are perfect squares are 202^0, 222^2, 242^4, 262^6, 282^8 =5= 5

Similarly, in 353 5, the factors which are perfect squares are 303^0, 323^2, 343^4 =3= 3

In 545 4, the factors which are perfect squares are 505^0, 525^2, 545^4 =3= 3

Number of perfect squares greater than 1 =5×3×31= 5 \times 3 \times 3 - 1

=44= 44

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