Question 18.

A circle is inscribed in a rhombus with diagonals 12 cm and 16 cm. The ratio of the area of the circle to the area of the rhombus is

A
2π15\frac{2π}{15}
B
6π25\frac{6π}{25}
C
3π25\frac{3π}{25}
D
5π18\frac{5π}{18}

Question Explanation

Text Explanation


Let the length of radius be ‘rr’.

From the above diagram,

x2+r2=62x^2 +r^2 = 6^2 ....(i)

(10x)2+r2=82(10 - x)^2 + r^2 = 8^2 ....(ii)

Subtracting (i) from (ii), we get: 

x=3.6x = 3.6 => r2=36(3.6)2r^2 = 36 - (3.6)^2 = 23.0423.04 ==> r2=36(3.6)2r^2 = 36 - (3.6)^2 = 23.0423.04

Area of circle = πr2=23.04π\pi r^2 = 23.04 \pi 

Area of rhombus = 1/2*d1*d2 = 1/2*12*16 = 96.

.’. Ratio of areas = 23.04π\pi / 96 = 6π25\frac{6 \pi}{25}

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