Question 16.

Gautam and Suhani, working together, can finish a job in 20 days. If Gautam does only 60% of his usual work on a day, Suhani must do 150% of her usual work on that day to exactly make up for it. Then, the number of days required by the faster worker to complete the job working alone is

A
B
C
D

Question Explanation

Text Explanation

Let 'g' and 's' be the efficiencies of Gautam and Suhani. Let W is the total amount of work.

=> g + s = W/20 (1 day work) ----(1)

Also Gautam doing only 60% => 3g/5 and Suhani doing 150% => 3s/2

=> 3g/5 + 3s/2 = W/20 (1 day work)

=> g + s = 3g5\frac{3g}{5} + 3s2\frac{3s}{2}

=> sg\frac{s}{g} = 45\frac{4}{5} => Gautam is the more efficient person.

Now, from the 1st equation

=> g + 4g5\frac{4g}{5} = W20\frac{W}{20}

=> 95\frac95g = W20\frac{W}{20}

=> g = W36\frac{W}{36}

=> Gautam takes 36 days to finish the complete work.

Video Explanation
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