Question 13.

Anil invests Rs 22000 for 6 years in a scheme with 4% interest per annum, compounded half-yearly. Separately, Sunil invests a certain amount in the same scheme for 5 years, and then reinvests the entire amount he receives at the end of 5 years, for one year at 10% simple interest. If the amounts received by both at the end of 6 years are equal, then the initial investment, in rupees, made by Sunil is

A
20480
B
20808
C
20640
D
20860

Question Explanation

Text Explanation

Let's take the amount invested by Sunil to be X. 

The amount received by Anil at the end of 6 years would be 22000(1+42× 100)6× 2=22000(1.02)1222000\left(1+\frac{4}{2\times\ 100}\right)^{6\times\ 2}=22000\left(1.02\right)^{12}

The amount received by Sunil at the end of 5 years would be X(1.02)10X\left(1.02\right)^{10}

In the 6th year, Sunil invests this at a simple interest of 10%, giving him an interest of X(1.02)10× 0.1X\left(1.02\right)^{10}\times\ 0.1

Giving the total amount with him at the end of 6 years to be X(1.02)10× (1+0.1)X\left(1.02\right)^{10}\times\ \left(1+0.1\right)

Equating the final amount with Sunil and Anil, we get:

X(1.02)10× (1.1)=22000(1.02)12X\left(1.02\right)^{10}\times\ \left(1.1\right)=22000\left(1.02\right)^{12}

X=22000(1.02)21.1=20808X=\frac{22000\left(1.02\right)^2}{1.1}=20808

Therefore, Option B is the correct answer. 

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