Question 11.

The number of distinct real roots of the equation (x+1x)2(x + \frac{1}{x})^{2} - 3(x + 1x\frac{1}{x} ) + 2 = 0 equals

A
B
C
D

Question Explanation

Text Explanation

Let a=x+1xa = x + \frac{1}{x}

So, the given equation is a23a+2=0a^2 - 3a + 2 = 0

So, aa can be either 22 or 11.

If a=1a = 1, x+1x=1x + \frac{1}{x} = 1 and it has no real roots.

If a=2a = 2, x+1x=2x + \frac{1}{x} = 2 and it has exactly one real root which is x=1x = 1.

So, the total number of distinct real roots of the given equation is 1

Video Explanation
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