Question 1.

If x1x_{1} = -1 and xmx_{m} = xm+1x_{m + 1} + (m + 1) for every positive integer m, then x100x_{100} equals

A
-5050
B
-5051
C
-5150
D
-5151
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Question Explanation

Text Explanation

x1=1x_1 = -1

x1=x2+2x2=x12=3x_1 = x_2 + 2 \Rightarrow x_2 = x_1 - 2 = -3

Similarly,

x3=x15=6x_3 = x_1 - 5 = -6

x4=10x_4 = -10

The series is -1, -3, -6, -10, -15, \ldots


When the differences are in AP, then the nth term is n(n+1)2-\frac{n(n+1)}{2}

x100=100(100+1)2=5050x_{100} = -\frac{100(100+1)}{2} = -5050

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