Question 22.

While rechecking her original notes to re-enter the smudged values of A and B in the records, the student found that one of the eleven recorded work experience values that did not get smudged was recorded wrongly as half of its correct value. After re-entering the values of A and B, and correcting the wrongly recorded value, she recalculated all the summary measures. The recalculated average value was 15. What is the value of B?

A
7
B
9
C
10
D
12

Question Explanation

Text Explanation

That is not one of the eleven values that we already have; this must mean that one of the missing values, A or B, must be 2

Since we are given that A is less than B, it must be A, which is equal to 2.

Now, writing down the twelve known numbers,

2, 5, 6, 7, 8, 12, 16, 19, 21, 21, 27, 29

we are also provided that the median of the data set was 12, which would be possible if the value 12 was shifted from the 6th position to the 7th position.

This must mean that the other missing value would also be in the first 6 values of the data set, lying in the range 2B122\le B\le12

Now, narrowing down our focus to the lower hinge, the value is given to be 6.5

The first six values would be 2, 5, 6, 7, 8 and one unknown value

The lower hinge would be 6.5 only if the missing value appears after 7

Narrowing down the possible values of B to be 7, 8, 9, 10, 11, 12

In the context of the third question, we are given that the average of the 13 values was 15, meaning that the sum of the 13 values was 195

As we calculated previously, the sum with the value we had would be 173 +B

we also have to add the mistaken value once more to this number to get 195

Let's take the unknown number to be U, giving us the equation

173 + B+ U = 195

B+U = 22

Where B must be one of 7, 8, 9, 10, 11 or 12

And U must be one of 5, 6, 7, 8, 12, 16, 19, 21, 21, 27, 29

trying to substitute the values of B into the equation, the only value which yields valid values for both B and U would be 10

Therefore, Option C is the correct answer. 

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