IPMAT indore 2021 Complete Paper Solution
Question 1.

The number of positive integers that divide (1890) × (130) × (170) and are not divisible by 45 is:
The number of positive integers that divide (1890) × (130) × (170) and are not divisible by 45 is:
Question 2.

Suppose that a real-valued function f(x) of real numbers satisfies f(x + xy) = f(x) + f(xy) for all real x, y, and that f(2020) = 1. Compute f(2021).
Suppose that a real-valued function f(x) of real numbers satisfies f(x + xy) = f(x) + f(xy) for all real x, y, and that f(2020) = 1. Compute f(2021).
Question 3.

The writer of the passage suggests that
The writer of the passage suggests that
Question 4.

Suppose that log2[log3(log4a)] = log3[log4(log2b)] = log4[log2(log3c)] = 0 then the value of a + b + c is
Suppose that log2[log3(log4a)] = log3[log4(log2b)] = log4[log2(log3c)] = 0 then the value of a + b + c is
Question 5.

The sum up to 10 terms of the series 1 × 3 + 5 × 7 + 9 × 11 + . . is
The sum up to 10 terms of the series 1 × 3 + 5 × 7 + 9 × 11 + . . is
Question 6.

The passage points out that an important difference between traditional media and social media is that
The passage points out that an important difference between traditional media and social media is that
Question 7.

It is given that the sequence {xn} satisfies x1 = 0, xn+1 = xn + 1 + for n = 1,2, . . . . . Then x31 is
It is given that the sequence {xn} satisfies x1 = 0, xn+1 = xn + 1 + for n = 1,2, . . . . . Then x31 is
Question 8.

Social media is dangerous in its ability to influence opinion in readers through
Social media is dangerous in its ability to influence opinion in readers through
Question 9.

Let Sn be sum of the first n terms of an A.P. {an}. If S5 = S9 , what is the ratio of a3 : a5
Let Sn be sum of the first n terms of an A.P. {an}. If S5 = S9 , what is the ratio of a3 : a5
Question 10.

If A, B and A + B are non singular matrices and AB = BA then 2A - B - A(A + B)-1A + B(A + B)-1B equals
If A, B and A + B are non singular matrices and AB = BA then 2A - B - A(A + B)-1A + B(A + B)-1B equals